What is the integral of (-2200x)/(sqrt(25-x^2)) ?

The integral of (-2200x)/(sqrt(25-x^2)) is 2200sqrt(25-x^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (-2200x)/(sqrt(25-x^2))

\int \frac{- 2200 x}{25 - x ^{2}} d x

2200 25 - x^{2} + C

Solution steps

\int \frac{- 2200 x}{25 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2200 \cdot \int \frac{x}{25 - x ^{2}} d x

Apply u-substitution

: \int - \frac{1}{2 u} d u

= - 2200 \cdot \int - \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2200 (- \frac{1}{2} \cdot \int \frac{1}{u} d u)

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= - 2200 (- \frac{1}{2} \cdot 2 u^{\frac{1}{2}})

Substitute back

u = 25 - x^{2}

= - 2200 (- \frac{1}{2} \cdot 2 (25 - x^{2})^{\frac{1}{2}})

Simplify

- 2200 (- \frac{1}{2} \cdot 2 (25 - x^{2})^{\frac{1}{2}}) : 2200 25 - x^{2}

= 2200 25 - x^{2}

Add a constant to the solution

= 2200 25 - x^{2} + C

\int \frac{e ^{x}}{e ^{2 x} + 3} d x

y^{^{'}} - 5 y = 10

\frac{d}{d x} (x^{9} ln (x))

\frac{d y}{d x} = - \frac{3 x}{y}

\frac{d}{d x} ((x^{2} + 3 x - 11)^{50})

What is the integral of (-2200x)/(sqrt(25-x^2)) ?
The integral of (-2200x)/(sqrt(25-x^2)) is 2200sqrt(25-x^2)+C