What is the derivative of e^{at}sin(bt) ?

The derivative of e^{at}sin(bt) is 0

What is the first derivative of e^{at}sin(bt) ?

The first derivative of e^{at}sin(bt) is 0

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\frac{d}{d x} (e^{a t} sin (b t))

0

Solution steps

\frac{d}{d x} (e^{a t} sin (b t))

Treat

a, b, t

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\int 3 x^{- 2} d x

\int cos (4 θ) d θ

\int_{2}^{5} x x - 1 d x

y = \frac{t}{4 t - 5}

y^{^{''}} + y^{^{'}} + y = sin^{2} (x)

What is the derivative of e^{at}sin(bt) ?
The derivative of e^{at}sin(bt) is 0
What is the first derivative of e^{at}sin(bt) ?
The first derivative of e^{at}sin(bt) is 0