What is the integral from 1 to 2 of 2x^2 ?

The integral from 1 to 2 of 2x^2 is 14/3

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integral from 1 to 2 of 2x^2

\int_{1}^{2} 2 x^{2} d x

\frac{14}{3}

Decimal

4.66666 \dots

Solution steps

\int_{1}^{2} 2 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{2}

= 2 [\frac{x ^{3}}{3}]_{1}^{2}

Compute the boundaries:

\frac{7}{3}

= 2 \cdot \frac{7}{3}

Simplify

= \frac{14}{3}

y = cos (5 x)

\int_{0}^{\frac{1}{3}} arcsin (3 y) d y

x \to π lim (\frac{3 x + 1}{1 - x})

\frac{d}{d x} ((ln (3 x))^{2})

x^{3}, x^{2} + x, - 1, 2

What is the integral from 1 to 2 of 2x^2 ?
The integral from 1 to 2 of 2x^2 is 14/3