What is (\partial)/(\partial y)(xsin(2y)) ?

The answer to (\partial)/(\partial y)(xsin(2y)) is xcos(2y)*2

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(\partial)/(\partial y)(xsin(2y))

\frac{\partial}{\partial y} (x sin (2 y))

x cos (2 y) \cdot 2

Solution steps

\frac{\partial}{\partial y} (x sin (2 y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial y} (sin (2 y))

Apply the chain rule:

cos (2 y) \frac{\partial}{\partial y} (2 y)

= cos (2 y) \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (2 y) = 2

= x cos (2 y) \cdot 2

y = 3 x^{3} - x^{2} + 2, (2, 22)

x \to - 1 lim (\frac{∣ x ∣ - 1}{x + 1})

h \to 0 lim (\frac{7 ( a + h ) ^{2} - 7 a ^{2}}{h})

f (x) = \frac{x ^{2}}{x ^{2} - 1}

\int \frac{1}{sin ( 5 x ) cos ( 5 x )} d x

What is (\partial)/(\partial y)(xsin(2y)) ?
The answer to (\partial)/(\partial y)(xsin(2y)) is xcos(2y)*2