What is the derivative of y=x^2+4 ?

The derivative of y=x^2+4 is 2x

What is the first derivative of y=x^2+4 ?

The first derivative of y=x^2+4 is 2x

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derivative of

y = x^{2} + 4

2 x

Solution steps

\frac{d}{d x} (x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4) = 0

= 2 x + 0

Simplify

= 2 x

y^{^{''}} + 16 y = e^{3 x}

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