What is the derivative of 4x^2+2x ?

The derivative of 4x^2+2x is 8x+2

What is the first derivative of 4x^2+2x ?

The first derivative of 4x^2+2x is 8x+2

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\frac{d}{d x} (4 x^{2} + 2 x)

8 x + 2

Solution steps

\frac{d}{d x} (4 x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (2 x) = 2

= 8 x + 2

\int lo g_{10} (x) d x

\frac{d}{d x} (arcsec (5 x^{4}))

\frac{\partial}{\partial y} (e^{3 x} sin (2 y))

cos (3 y)

\frac{d}{d x} (e^{- 5 x^{4}})

What is the derivative of 4x^2+2x ?
The derivative of 4x^2+2x is 8x+2
What is the first derivative of 4x^2+2x ?
The first derivative of 4x^2+2x is 8x+2