What is the derivative of h(x)= 1/((-x^2+x-2)^5) ?

The derivative of h(x)= 1/((-x^2+x-2)^5) is -(5(-2x+1))/((-x^2+x-2)^6)

What is the first derivative of h(x)= 1/((-x^2+x-2)^5) ?

The first derivative of h(x)= 1/((-x^2+x-2)^5) is -(5(-2x+1))/((-x^2+x-2)^6)

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derivative of

h (x) = \frac{1}{( - x ^{2} + x - 2 ) ^{5}}

- \frac{5 ( - 2 x + 1 )}{( - x ^{2} + x - 2 ) ^{6}}

Solution steps

\frac{d}{d x} (\frac{1}{( - x ^{2} + x - 2 ) ^{5}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((- x^{2} + x - 2)^{- 5})

Apply the chain rule:

- \frac{5}{( - x ^{2} + x - 2 ) ^{6}} \frac{d}{d x} (- x^{2} + x - 2)

= - \frac{5}{( - x ^{2} + x - 2 ) ^{6}} \frac{d}{d x} (- x^{2} + x - 2)

\frac{d}{d x} (- x^{2} + x - 2) = - 2 x + 1

= - \frac{5}{( - x ^{2} + x - 2 ) ^{6}} (- 2 x + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{5 ( - 2 x + 1 )}{( - x ^{2} + x - 2 ) ^{6}}

\frac{\partial}{\partial x} (\frac{x ^{2} + 2 y}{x ^{3} - y ^{2}})

\frac{d}{d x} (ln (x x^{2} - 5))

n = 0 \sum \infty \frac{x ^{n}}{4 ^{n}}

2 x^{2}, at 2

\frac{d}{d x} (x e^{2 x - y^{2}})

What is the derivative of h(x)= 1/((-x^2+x-2)^5) ?
The derivative of h(x)= 1/((-x^2+x-2)^5) is -(5(-2x+1))/((-x^2+x-2)^6)
What is the first derivative of h(x)= 1/((-x^2+x-2)^5) ?
The first derivative of h(x)= 1/((-x^2+x-2)^5) is -(5(-2x+1))/((-x^2+x-2)^6)