What is the derivative of x^2+y^2-1 ?

The derivative of x^2+y^2-1 is 2x+2y(dy)/(dx)

What is the first derivative of x^2+y^2-1 ?

The first derivative of x^2+y^2-1 is 2x+2y(dy)/(dx)

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\frac{d}{d x} (x^{2} + y^{2} - 1)

2 x + 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{2} + y^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (y^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

\frac{d}{d x} (1) = 0

= 2 x + 2 y \frac{d y}{d x} - 0

Simplify

= 2 x + 2 y \frac{d y}{d x}

\frac{d}{d x} (e^{s i n (x)})

x \to 2 lim (\frac{x - 2}{( x - 2 )})

y = x + sin (x)

\frac{d}{d x} ((2 x^{3} - 12 x)^{\frac{4}{3}})

\frac{\partial}{\partial x} (\frac{x}{x ^{2} + 4 y ^{2}})

What is the derivative of x^2+y^2-1 ?
The derivative of x^2+y^2-1 is 2x+2y(dy)/(dx)
What is the first derivative of x^2+y^2-1 ?
The first derivative of x^2+y^2-1 is 2x+2y(dy)/(dx)