What is the limit as x approaches+0+of arctan(2/x) ?

The limit as x approaches+0+of arctan(2/x) is pi/2

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limit as x approaches+0+of arctan(2/x)

x \to + 0 + lim (arctan (\frac{2}{x}))

\frac{π}{2}

Decimal

1.57079 \dots

Solution steps

x \to 0 + lim (arctan (\frac{2}{x}))

Apply the Limit Chain Rule:

\frac{π}{2}

= \frac{π}{2}

\frac{d}{d x} \frac{8}{( x ^{3} + x ^{2} + 1 ) ^{3}}

\int sin (a x) d x

y = \frac{2 x - sin ( 2 x )}{x ^{2} + cos ( x ^{2} )}

\int \frac{( 1 0 ^{2 x} + 1 )}{( 1 0 ^{x} - 1 )} d x

\int \frac{( x ^{2} - 16 )}{( x - 4 )} d x

What is the limit as x approaches+0+of arctan(2/x) ?
The limit as x approaches+0+of arctan(2/x) is pi/2