What is (\partial)/(\partial x)(2x^2+3y^2) ?

The answer to (\partial)/(\partial x)(2x^2+3y^2) is 4x

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(\partial)/(\partial x)(2x^2+3y^2)

\frac{\partial}{\partial x} (2 x^{2} + 3 y^{2})

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + 3 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (3 y^{2})

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (3 y^{2}) = 0

= 4 x + 0

Simplify

= 4 x

\frac{d y}{d x} - 2 x y = 6 x

x \to 2 lim (\frac{\frac{2}{x} - 1}{x - 2})

x \to π lim (\frac{sin ( x )}{x})

\frac{d}{d x} (1 - sin (x))

f

What is (\partial)/(\partial x)(2x^2+3y^2) ?
The answer to (\partial)/(\partial x)(2x^2+3y^2) is 4x