What is the solution for y^{''}+y=cos(x) ?

The solution for y^{''}+y=cos(x) is y=c_{1}cos(x)+c_{2}sin(x)+(xsin(x))/2

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y^{''}+y=cos(x)

y^{^{''}} + y = cos (x)

y = c_{1} cos (x) + c_{2} sin (x) + \frac{x sin ( x )}{2}

Solution steps

y^{''} (x) + y = cos (x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + \frac{x sin ( x )}{2}

y = c_{1} cos (x) + c_{2} sin (x) + \frac{x sin ( x )}{2}

f (x) = x^{3} - 27 x

\frac{d}{d x} (x^{x l n (x)})

\int e^{- p x} d x

(7 x^{6} + 8 x^{3})^{4}

\int \frac{y ^{2} - x ^{2}}{( x ^{2} + y ^{2} ) ^{2}} d y

What is the solution for y^{''}+y=cos(x) ?
The solution for y^{''}+y=cos(x) is y=c_{1}cos(x)+c_{2}sin(x)+(xsin(x))/2