What is the tangent of f(x)=e^x,\at x=ln(11) ?

The tangent of f(x)=e^x,\at x=ln(11) is y=11x+11-11ln(11)

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tangent of f(x)=e^x,\at x=ln(11)

tangent of

f (x) = e^{x}, at x = ln (11)

y = 11 x + 11 - 11 ln (11)

Solution steps

Find the tangent point:

(ln (11), 11)

Find the slope of

f (x) = e^{x} : \frac{df ( x )}{d x} = e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 11

Find the line with slope m=

11

and passing through

(ln (11), 11) : y = 11 x + 11 - 11 ln (11)

y = 11 x + 11 - 11 ln (11)

f (x) = 8 x - x^{2}

\frac{\partial}{\partial x} (ln (3 x^{2} + 2 y^{3}))

\int \frac{e ^{x}}{4 + 9 e ^{2 x}} d x

- x^{2} + 26 x + 920

y^{^{'}} = \frac{( 1 + x )}{x y ^{6}}

What is the tangent of f(x)=e^x,\at x=ln(11) ?
The tangent of f(x)=e^x,\at x=ln(11) is y=11x+11-11ln(11)