What is the solution for (dy)/(dx)= x/y ,y(0)=-8 ?

The solution for (dy)/(dx)= x/y ,y(0)=-8 is y=-sqrt(x^2+64)

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(dy)/(dx)= x/y ,y(0)=-8

\frac{d y}{d x} = \frac{x}{y}, y (0) = - 8

y = - x^{2} + 64

Solution steps

\frac{d y}{d x} = \frac{x}{y}

Solve separable ODE:

y = - x^{2} + 64

y = - x^{2} + 64

\int c e^{- x} d x

\int \frac{sin ( 7 e ^{- 5 x} )}{e ^{5 x}} d x

\int \frac{x ^{2}}{x ^{2} - 9} d x

y^{^{'}} = y (3 - y) - \frac{9}{4}

\frac{d y}{d x} = 5 y e^{x + 9}

What is the solution for (dy)/(dx)= x/y ,y(0)=-8 ?
The solution for (dy)/(dx)= x/y ,y(0)=-8 is y=-sqrt(x^2+64)