What is the first derivative of e^3x ?

The first derivative of e^3x is e^3

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derivative of e^3x

\frac{d}{d x} (e^{3} x)

e^{3}

Solution steps

\frac{d}{d x} (e^{3} x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{3} \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= e^{3} \cdot 1

Simplify

= e^{3}

\frac{\partial}{\partial x} (4 x^{8 y})

\int x 2 - 1 - x^{2} d x

\int (arccos (x))^{2} d x

y^{^{'}} + 6 y = e^{x}

y = x^{2} 16 - x^{2}