What is the integral from 1 to 2 of 5/(x^2) ?

The integral from 1 to 2 of 5/(x^2) is 5/2

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integral from 1 to 2 of 5/(x^2)

\int_{1}^{2} \frac{5}{x ^{2}} d x

\frac{5}{2}

Decimal

2.5

Solution steps

\int_{1}^{2} \frac{5}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{1}^{2} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{2}

= 5 [- \frac{1}{x}]_{1}^{2}

Compute the boundaries:

\frac{1}{2}

= 5 \cdot \frac{1}{2}

Simplify

= \frac{5}{2}

f (x) = 8 x - 3, at x = 64

\frac{d}{d y} (y x^{2})

y^{^{''}} + 11 y^{^{'}} + 22 y = 3468 e^{2 t} cos (12 t)

\int_{0}^{1} π (e^{x} + 1)^{2} d x

2 y \frac{d y}{d x} + y^{2} cot (x) = csc (x)

What is the integral from 1 to 2 of 5/(x^2) ?
The integral from 1 to 2 of 5/(x^2) is 5/2