What is the tangent of f(x)=sqrt(3x+13),(12,7) ?

The tangent of f(x)=sqrt(3x+13),(12,7) is y= 3/14 x+31/7

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tangent of f(x)=sqrt(3x+13),(12,7)

tangent of

f (x) = 3 x + 13, (12, 7)

y = \frac{3}{14} x + \frac{31}{7}

Solution steps

Find the slope of

f (x) = 3 x + 13 : \frac{df ( x )}{d x} = \frac{3}{2 3 x + 13}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{14}

Find the line with slope m=

\frac{3}{14}

and passing through

(12, 7) : y = \frac{3}{14} x + \frac{31}{7}

y = \frac{3}{14} x + \frac{31}{7}

y = 3 (ln (x) + 1)

\frac{d}{d x} (2 cos (5 x))

h \to 0 lim ((1 + \frac{h}{y})^{\frac{1}{h}})

\int (2 + \frac{1}{x})^{2} d x

n = 1 \sum \infty (\frac{2}{5})^{n}

What is the tangent of f(x)=sqrt(3x+13),(12,7) ?
The tangent of f(x)=sqrt(3x+13),(12,7) is y= 3/14 x+31/7