What is the solution for y^'+y+3sin(x)=0 ?

The solution for y^'+y+3sin(x)=0 is y=-(3(sin(x)-cos(x)))/2+(c_{1})/(e^x)

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y^'+y+3sin(x)=0

y^{^{'}} + y + 3 sin (x) = 0

y = - \frac{3 ( sin ( x ) - cos ( x ) )}{2} + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) + y + 3 sin (x) = 0

Solve linear ODE:

y = - \frac{3 ( sin ( x ) - cos ( x ) )}{2} + \frac{c _{1}}{e ^{x}}

y = - \frac{3 ( sin ( x ) - cos ( x ) )}{2} + \frac{c _{1}}{e ^{x}}

y = x^{2} - 14, y = 7 - 4 x

\frac{d}{d x} (\frac{1}{x ^{13}})

\int x^{2} - 2 x d x

\frac{1}{s ( s + 2 ) ^{2}}

y^{^{''}} = - 9 y

What is the solution for y^'+y+3sin(x)=0 ?
The solution for y^'+y+3sin(x)=0 is y=-(3(sin(x)-cos(x)))/2+(c_{1})/(e^x)