What is the integral from-1 to 1 of e^x-x^2+1 ?

The integral from-1 to 1 of e^x-x^2+1 is e+4/3-1/e

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integral from-1 to 1 of e^x-x^2+1

\int_{- 1}^{1} e^{x} - x^{2} + 1 d x

e + \frac{4}{3} - \frac{1}{e}

Decimal

3.68373 \dots

Solution steps

\int_{- 1}^{1} e^{x} - x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} e^{x} d x - \int_{- 1}^{1} x^{2} d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} e^{x} d x = e - \frac{1}{e}

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} 1 d x = 2

= e - \frac{1}{e} - \frac{2}{3} + 2

Combine the fractions

2 - \frac{2}{3} : \frac{4}{3}

= e + \frac{4}{3} - \frac{1}{e}

\int \frac{x ^{2}}{x ^{2} + x ^{4}} d x

\int_{0}^{1} 5 cos (\frac{π t}{2}) d t

y^{^{''}} - 4 y^{^{'}} = 16 t

\int \frac{1}{( a + b x ) ^{\frac{1}{3}}} d x

x^{2} y d x + x^{3} d y = 0

What is the integral from-1 to 1 of e^x-x^2+1 ?
The integral from-1 to 1 of e^x-x^2+1 is e+4/3-1/e