What is the solution for (dy)/(dx)=(x+y-2)^2 ?

The solution for (dy)/(dx)=(x+y-2)^2 is y=tan(x+c_{1})-x+2

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(dy)/(dx)=(x+y-2)^2

\frac{d y}{d x} = (x + y - 2)^{2}

y = tan (x + c_{1}) - x + 2

Solution steps

\frac{d y}{d x} = (x + y - 2)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x + 2

y = tan (x + c_{1}) - x + 2

\frac{d ^{2}}{d x ^{2}} (3 x - 7)

2 x^{2} + 5 x + 6, (- 2, 0)

x \to \infty lim (- 1^{x})

\frac{d}{d x} ((sin (x))^{- 1})

x \to - \infty lim (\frac{x ^{3} + 1}{x ^{2} - 1})

What is the solution for (dy)/(dx)=(x+y-2)^2 ?
The solution for (dy)/(dx)=(x+y-2)^2 is y=tan(x+c_{1})-x+2