What is the integral of ((-2cos(x)))/(sin^2(x)) ?

The integral of ((-2cos(x)))/(sin^2(x)) is 2csc(x)+C

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integral of ((-2cos(x)))/(sin^2(x))

\int \frac{( - 2 cos ( x ) )}{sin ^{2} ( x )} d x

2 csc (x) + C

Solution steps

\int \frac{- 2 cos ( x )}{sin ^{2} ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{cos ( x )}{sin ^{2} ( x )} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= - 2 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - 2 (- \frac{1}{u})

Substitute back

u = sin (x)

= - 2 (- \frac{1}{sin ( x )})

Simplify

- 2 (- \frac{1}{sin ( x )}) : 2 csc (x)

= 2 csc (x)

Add a constant to the solution

= 2 csc (x) + C

\frac{3 x}{4}

\int \frac{1}{25 x ^{2} - 49} d x

\int \frac{6 - x}{4 x ^{2} - 12 x + 7} d x

t y^{^{'}} + 3 y = t^{2} - t + 7

x \to 0 lim (\frac{1}{x})

What is the integral of ((-2cos(x)))/(sin^2(x)) ?
The integral of ((-2cos(x)))/(sin^2(x)) is 2csc(x)+C