What is the limit as x approaches 0 of 1/x+3 ?

The limit as x approaches 0 of 1/x+3 is diverges

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limit as x approaches 0 of 1/x+3

x \to 0 lim (\frac{1}{x} + 3)

diverges

Solution steps

x \to 0 lim (\frac{1}{x} + 3)

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x} + 3) = \infty

x \to 0 - lim (\frac{1}{x} + 3) = - \infty

= diverges

\frac{d}{d x} (e^{(x + y)})

\frac{d}{d x} (arcsin (a x))

\frac{( x + 9 )}{( x + 4 )}

3 sin (x), 0, 0.6 π, 4 cos (x)

y^{^{''}} + 9 y = e^{- t}

What is the limit as x approaches 0 of 1/x+3 ?
The limit as x approaches 0 of 1/x+3 is diverges