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Popular >

y^'=3y+x

Solution

y^{^{'}} = 3 y + x

Solution

y = - \frac{3 x + 1}{9} + c_{1} e^{3 x}

Solution steps

y^{'} (x) = 3 y + x

Solve linear ODE:

y = - \frac{3 x + 1}{9} + c_{1} e^{3 x}

y = - \frac{3 x + 1}{9} + c_{1} e^{3 x}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=3y+x ?
The solution for y^'=3y+x is y=-(3x+1)/9+c_{1}e^{3x}