What is (\partial)/(\partial y)(xy^2-x^3y) ?

The answer to (\partial)/(\partial y)(xy^2-x^3y) is 2xy-x^3

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(\partial)/(\partial y)(xy^2-x^3y)

\frac{\partial}{\partial y} (x y^{2} - x^{3} y)

2 x y - x^{3}

Solution steps

\frac{\partial}{\partial y} (x y^{2} - x^{3} y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x y^{2}) - \frac{\partial}{\partial y} (x^{3} y)

\frac{\partial}{\partial y} (x y^{2}) = 2 x y

\frac{\partial}{\partial y} (x^{3} y) = x^{3}

= 2 x y - x^{3}

\int 36 - t^{2} d t

\int x 2^{x} d x

f (x) = 2 x^{9} e x

\frac{d}{d x} (4 x + \frac{1}{x})

n = 1 \sum \infty \frac{1}{n \cdot ln ( n )}

What is (\partial)/(\partial y)(xy^2-x^3y) ?
The answer to (\partial)/(\partial y)(xy^2-x^3y) is 2xy-x^3