What is the tangent of f(x)=(-4x)/(x^2+1),(-1,2) ?

The tangent of f(x)=(-4x)/(x^2+1),(-1,2) is y=2

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tangent of f(x)=(-4x)/(x^2+1),(-1,2)

tangent of

f (x) = \frac{- 4 x}{x ^{2} + 1}, (- 1, 2)

y = 2

Solution steps

Find the slope of

f (x) = \frac{- 4 x}{x ^{2} + 1} : \frac{df ( x )}{d x} = - \frac{4 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{- 4 x}{x ^{2} + 1}

(- 1, 2) : m = 0

Find the line with slope m=

0

and passing through

(- 1, 2) : y = 2

y = 2

cos (θ^{2})

\int x (x^{2} + 4)^{5} d x

\frac{\partial}{\partial x} (e^{y x})

\int \frac{e ^{2 y}}{e ^{y} - 1} d y

\int sec^{3} (5 x) d x

What is the tangent of f(x)=(-4x)/(x^2+1),(-1,2) ?
The tangent of f(x)=(-4x)/(x^2+1),(-1,2) is y=2