What is the first derivative of y=4x^2 ?

The first derivative of y=4x^2 is 8x

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derivative of y=4x^2

derivative of

y = 4 x^{2}

8 x

Solution steps

\frac{d}{d x} (4 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot 2 x^{2 - 1}

Simplify

= 8 x

f (x) = ln (7)

\int_{0}^{2} x^{3} e^{- x^{2}} d x

x \to 0 lim (\frac{1 + x}{x ^{2}})

4 (x - (\frac{1}{x})^{4})

f (x) = \frac{x}{3}