What is the limit as t approaches 1 of sqrt(t+5) ?

The limit as t approaches 1 of sqrt(t+5) is square root of 6

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limit as t approaches 1 of sqrt(t+5)

t \to 1 lim (t + 5)

6

Decimal

2.44948 \dots

Solution steps

t \to 1 lim (t + 5)

Plug in the value

t = 1

= 1 + 5

Simplify

= 6

\frac{d}{d t} (3^{t})

\frac{d y}{d x} = 1 - (10 x - y + 4)^{2}

3 y^{^{''}} + 3 y^{^{'}} - 2 y = 0

e^{(x^{2})}

x \to 1 + lim (\frac{2 x + 1}{x - 1})

What is the limit as t approaches 1 of sqrt(t+5) ?
The limit as t approaches 1 of sqrt(t+5) is square root of 6