What is the integral of e^{(-1-sqrt(13)i)t} ?

The integral of e^{(-1-sqrt(13)i)t} is i(-1+sqrt(13))/(14)e^{(-1-sqrt(13)i)t}+C

Popular >

integral of e^{(-1-sqrt(13)i)t}

\int e^{(- 1 - 13 i) t} d t

i \frac{- 1 + 13}{14} e^{(- 1 - 13 i) t} + C

Solution steps

\int e^{(- 1 - 13 i) t} d t

Apply u-substitution

: \int i \frac{( - 1 + 13 ) e ^{u}}{14} d u

= \int i \frac{( - 1 + 13 ) e ^{u}}{14} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= i \frac{- 1 + 13}{14} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= i \frac{- 1 + 13}{14} e^{u}

Substitute back

u = (- 1 - 13 i) t

= i \frac{- 1 + 13}{14} e^{(- 1 - 13 i) t}

Add a constant to the solution

= i \frac{- 1 + 13}{14} e^{(- 1 - 13 i) t} + C

\int \frac{1}{2 u + 1} d u

x \to 1 + lim (ln (3 x^{2} - x - 2))

f (x) = x^{2} + 1, at x = 3

x \to 3 lim (\frac{5}{( x - 3 ) ^{2}})

\frac{d y}{d x} = \frac{1}{x} (y^{2} + y), y (1) = 0.5

What is the integral of e^{(-1-sqrt(13)i)t} ?
The integral of e^{(-1-sqrt(13)i)t} is i(-1+sqrt(13))/(14)e^{(-1-sqrt(13)i)t}+C