What is the solution for e^ydx-e^{-x}dy=0,y(0)=0 ?

The solution for e^ydx-e^{-x}dy=0,y(0)=0 is y=-ln(-e^x-c_{1})

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e^ydx-e^{-x}dy=0,y(0)=0

e^{y} d x - e^{- x} d y = 0, y (0) = 0

y = - ln (- e^{x} - c_{1})

Solution steps

e^{y} d x - e^{- x} d y = 0

Solve separable ODE:

y = - ln (- e^{x} - c_{1})

y = - ln (- e^{x} - c_{1})

\frac{d ^{2}}{d r ^{2}} (π r^{2})

f (x) = \frac{x + 6}{e ^{x}}

n = 0 \sum \infty sec (n)

\int x^{3} (2 x + 5 - 3 x) d x

n = 1 \sum \infty e^{2 n}

What is the solution for e^ydx-e^{-x}dy=0,y(0)=0 ?
The solution for e^ydx-e^{-x}dy=0,y(0)=0 is y=-ln(-e^x-c_{1})