What is the derivative of e^{t^2} ?

The derivative of e^{t^2} is e^{t^2}*2t

What is the first derivative of e^{t^2} ?

The first derivative of e^{t^2} is e^{t^2}*2t

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derivative of

e^{t^{2}}

e^{t^{2}} \cdot 2 t

Solution steps

\frac{d}{d t} (e^{t^{2}})

Apply the chain rule:

e^{t^{2}} \frac{d}{d t} (t^{2})

= e^{t^{2}} \frac{d}{d t} (t^{2})

\frac{d}{d t} (t^{2}) = 2 t

= e^{t^{2}} \cdot 2 t

\frac{( s - 1 )}{s ( s ^{2} + s + 1 )}

\int \frac{x}{( 1 + x ^{2} ) 1 - x ^{4}} d x

x \frac{d y}{d x} = x tan (\frac{y}{x}) + y

(9 x^{6} + 2 x^{3})^{4}

y = 6 + 4 x^{2} - 2 x^{3}, at x = a

What is the derivative of e^{t^2} ?
The derivative of e^{t^2} is e^{t^2}*2t
What is the first derivative of e^{t^2} ?
The first derivative of e^{t^2} is e^{t^2}*2t