What is (\partial)/(\partial y)(2xy-3x^2) ?

The answer to (\partial)/(\partial y)(2xy-3x^2) is 2x

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(\partial)/(\partial y)(2xy-3x^2)

\frac{\partial}{\partial y} (2 x y - 3 x^{2})

2 x

Solution steps

\frac{\partial}{\partial y} (2 x y - 3 x^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y) - \frac{\partial}{\partial y} (3 x^{2})

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (3 x^{2}) = 0

= 2 x - 0

Simplify

= 2 x

x \to 1 lim (\frac{2 x + 1}{x + 2})

\frac{d}{d x} ((9 x^{2} - 3 x - 10) y^{^{''}} + (x^{2} + x) y^{^{'}} + (2 x - 1) y)

\frac{\partial}{\partial x} (tan (6 + 2 x^{2} y^{3} z^{2}))

\frac{d}{d x} (ln (- ln (1 - x)))

2 (\frac{e ^{2 t} - e ^{2 t}}{2}) sin (2 t)

What is (\partial)/(\partial y)(2xy-3x^2) ?
The answer to (\partial)/(\partial y)(2xy-3x^2) is 2x