What is the sum from m=1 to infinity of 3*(1/3) ?

The sum from m=1 to infinity of 3*(1/3) is diverges

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sum from m=1 to infinity of 3*(1/3)

m = 1 \sum \infty 3 \cdot (\frac{1}{3})

diverges

Solution steps

m = 1 \sum \infty 3 \cdot \frac{1}{3}

Every infinite sum of a non-zero constant diverges

= diverges

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What is the sum from m=1 to infinity of 3*(1/3) ?
The sum from m=1 to infinity of 3*(1/3) is diverges