What is the tangent of y=(sqrt(x))/(x+3),(1,0.25) ?

The tangent of y=(sqrt(x))/(x+3),(1,0.25) is y= 1/16 x+0.1875

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tangent of y=(sqrt(x))/(x+3),(1,0.25)

tangent of

y = \frac{x}{x + 3}, (1, 0.25)

y = \frac{1}{16} x + 0.1875

Solution steps

Find the slope of

y = \frac{x}{x + 3} : \frac{d y}{d x} = \frac{- x + 3}{2 x ( x + 3 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{16}

Find the line with slope m=

\frac{1}{16}

and passing through

(1, 0.25) : y = \frac{1}{16} x + 0.1875

y = \frac{1}{16} x + 0.1875

\frac{d}{d x} (\frac{1}{( 3 x ^{2} + x - 3 ) ^{9}})

f (x) = x^{x^{2}}

x \to 9 lim (25 - x)

\frac{\partial}{\partial x} (2 x y e^{x^{2}})

x \to 1 lim ((x - 2 [x])^{2})

What is the tangent of y=(sqrt(x))/(x+3),(1,0.25) ?
The tangent of y=(sqrt(x))/(x+3),(1,0.25) is y= 1/16 x+0.1875