What is the derivative of x^3+6x^2 ?

The derivative of x^3+6x^2 is 3x^2+12x

What is the first derivative of x^3+6x^2 ?

The first derivative of x^3+6x^2 is 3x^2+12x

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\frac{d}{d x} (x^{3} + 6 x^{2})

3 x^{2} + 12 x

Solution steps

\frac{d}{d x} (x^{3} + 6 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (6 x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

= 3 x^{2} + 12 x

5 x y (\frac{d y}{d x}) = 3

\int_{0}^{2} x 1 + 2 x^{2} d x

\int 3 + tan^{2} (x) d x

3 csc (x)

\int cos^{4} (11 x) d x

What is the derivative of x^3+6x^2 ?
The derivative of x^3+6x^2 is 3x^2+12x
What is the first derivative of x^3+6x^2 ?
The first derivative of x^3+6x^2 is 3x^2+12x