What is area 2,-5,y=2x^2+12,y=0 ?

The answer to area 2,-5,y=2x^2+12,y=0 is 518/3

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area 2,-5,y=2x^2+12,y=0

area

2, - 5, y = 2 x^{2} + 12, y = 0

\frac{518}{3}

Decimal

172.66666 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{2} 2 x^{2} + 12 d x

Solve

\int_{- 5}^{2} 2 x^{2} + 12 d x : \frac{518}{3}

The area is:

= \frac{518}{3}

x \to \infty lim (4 + \frac{1}{x})

\frac{\partial}{\partial x} (\frac{1}{3 x - 2})

\int sin (24 x) cos (17 x) d x

\int x - \frac{x ^{2}}{2} + c d x

n = 1 \sum \infty \frac{1}{n ^{2} + 6 n + 8}

What is area 2,-5,y=2x^2+12,y=0 ?
The answer to area 2,-5,y=2x^2+12,y=0 is 518/3