What is the derivative of 8e^{8t+5} ?

The derivative of 8e^{8t+5} is 64e^{8t+5}

What is the first derivative of 8e^{8t+5} ?

The first derivative of 8e^{8t+5} is 64e^{8t+5}

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derivative of

8 e^{8 t + 5}

64 e^{8 t + 5}

Solution steps

\frac{d}{d t} (8 e^{8 t + 5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d t} (e^{8 t + 5})

Apply the chain rule:

e^{8 t + 5} \frac{d}{d t} (8 t + 5)

= e^{8 t + 5} \frac{d}{d t} (8 t + 5)

\frac{d}{d t} (8 t + 5) = 8

= 8 e^{8 t + 5} \cdot 8

Simplify

= 64 e^{8 t + 5}

\int \frac{1}{5 - 8 x} d x

x \to 2 lim (2 x - 1)

(x^{2} + 1)^{^{'}}

\frac{d}{d x} (x y^{- 1})

\frac{\partial}{\partial x} (3 ln (\frac{2 x y}{5 z}))

What is the derivative of 8e^{8t+5} ?
The derivative of 8e^{8t+5} is 64e^{8t+5}
What is the first derivative of 8e^{8t+5} ?
The first derivative of 8e^{8t+5} is 64e^{8t+5}