What is (\partial)/(\partial x)(x+y-320) ?

The answer to (\partial)/(\partial x)(x+y-320) is 1

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(\partial)/(\partial x)(x+y-320)

\frac{\partial}{\partial x} (x + y - 320)

1

Solution steps

\frac{\partial}{\partial x} (x + y - 320)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (320)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (320) = 0

= 1 + 0 - 0

Simplify

= 1

x \to 4 lim (x - 2)

\frac{d}{d x} (e^{x^{2}} y) = x

\int_{0}^{7} x + 1 d x

\frac{\partial}{\partial x} (y)

\frac{d}{d x} (\frac{1}{( 1 + sec ( x ) ) ^{2}})

What is (\partial)/(\partial x)(x+y-320) ?
The answer to (\partial)/(\partial x)(x+y-320) is 1