What is the derivative of f(t)=sqrt(sin(4t)) ?

The derivative of f(t)=sqrt(sin(4t)) is 1/(2sqrt(sin(4t)))cos(4t)*4

What is the first derivative of f(t)=sqrt(sin(4t)) ?

The first derivative of f(t)=sqrt(sin(4t)) is 1/(2sqrt(sin(4t)))cos(4t)*4

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derivative of

f (t) = sin (4 t)

\frac{1}{2 sin ( 4 t )} cos (4 t) \cdot 4

Solution steps

\frac{d}{d t} (sin (4 t))

Apply the chain rule:

\frac{1}{2 sin ( 4 t )} \frac{d}{d t} (sin (4 t))

= \frac{1}{2 sin ( 4 t )} \frac{d}{d t} (sin (4 t))

\frac{d}{d t} (sin (4 t)) = cos (4 t) \cdot 4

= \frac{1}{2 sin ( 4 t )} cos (4 t) \cdot 4

x \to π lim (x sec (x))

\int_{- 2}^{- 1} 4 x^{3} + \frac{2}{x ^{3}} d x

\frac{d}{d x} (\frac{2 e ^{3 x} - 3}{x + 1})

\int a^{2} - x^{\frac{2}{3}} d x

x \to 0 lim (- 0. 5^{2} + 1)

What is the derivative of f(t)=sqrt(sin(4t)) ?
The derivative of f(t)=sqrt(sin(4t)) is 1/(2sqrt(sin(4t)))cos(4t)*4
What is the first derivative of f(t)=sqrt(sin(4t)) ?
The first derivative of f(t)=sqrt(sin(4t)) is 1/(2sqrt(sin(4t)))cos(4t)*4