What is the derivative of ln^2(x) ?

The derivative of ln^2(x) is (2ln(x))/x

What is the first derivative of ln^2(x) ?

The first derivative of ln^2(x) is (2ln(x))/x

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derivative of

ln^{2} (x)

\frac{2 ln ( x )}{x}

Solution steps

\frac{d}{d x} (ln^{2} (x))

Apply the chain rule:

2 ln (x) \frac{d}{d x} (ln (x))

= 2 ln (x) \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 ln (x) \frac{1}{x}

Simplify

2 ln (x) \frac{1}{x} : \frac{2 ln ( x )}{x}

= \frac{2 ln ( x )}{x}

\int π sin (n x) d x

\frac{d y}{d x} = \frac{x ^{2}}{( y ( 1 + x ^{2} ) )}

x \to 1 lim ((x - 1) ∣ x - 1 ∣)

x \to 0 - lim (2)

n = 0 \sum \infty \frac{( 2 ^{n} )}{9 ^{2 n + 1}}

What is the derivative of ln^2(x) ?
The derivative of ln^2(x) is (2ln(x))/x
What is the first derivative of ln^2(x) ?
The first derivative of ln^2(x) is (2ln(x))/x