What is the derivative of 2ax-1/(x^2) ?

The derivative of 2ax-1/(x^2) is 2a+2/(x^3)

What is the first derivative of 2ax-1/(x^2) ?

The first derivative of 2ax-1/(x^2) is 2a+2/(x^3)

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\frac{d}{d x} (2 a x - \frac{1}{x ^{2}})

2 a + \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (2 a x - \frac{1}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 a x) - \frac{d}{d x} (\frac{1}{x ^{2}})

\frac{d}{d x} (2 a x) = 2 a

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= 2 a - (- \frac{2}{x ^{3}})

Simplify

= 2 a + \frac{2}{x ^{3}}

\int \frac{5 x}{x ^{2}} d x

x^{3} - 4 x^{2} + 3 x, 0

(y + x) y^{^{'}} = y

\int_{0}^{π} x cos (2 x) d x

\frac{32}{( s ^{2} + 4 ^{2} ) ( s + 4 ) ^{2}}

What is the derivative of 2ax-1/(x^2) ?
The derivative of 2ax-1/(x^2) is 2a+2/(x^3)
What is the first derivative of 2ax-1/(x^2) ?
The first derivative of 2ax-1/(x^2) is 2a+2/(x^3)