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Popular >

y^'=4(y^2+1)

Solution

y^{^{'}} = 4 (y^{2} + 1)

Solution

y = tan (4 t + c_{1})

Solution steps

y^{'} (t) = 4 (y^{2} + 1)

Solve separable ODE:

y = tan (4 t + c_{1})

y = tan (4 t + c_{1})

Popular Examples

limit as x approaches infinity of 1/x-5

x \to \infty lim (\frac{1}{x} - 5)

limit as x approaches 3 of 4/(x^2+2x+3)

x \to 3 lim (\frac{4}{x ^{2} + 2 x + 3})

derivative of 14-1/2 x^{-3}

\frac{d}{d x} (14 - \frac{1}{2} x^{- 3})

derivative of y=arcsin(8x+1)derivative of

y = arcsin (8 x + 1)

derivative of cos^2(2x^4-4)

\frac{d}{d x} (cos^{2} (2 x^{4} - 4))

Frequently Asked Questions (FAQ)

What is the solution for y^'=4(y^2+1) ?
The solution for y^'=4(y^2+1) is y=tan(4t+c_{1})