What is the integral of 1.8^{0.045x} ?

The integral of 1.8^{0.045x} is 37.80661…*1.02680…^x+C

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integral of 1.8^{0.045x}

\int 1. 8^{0.045 x} d x

37.80661 \dots \cdot 1.02680 \dots^{x} + C

Solution steps

\int 1. 8^{0.045 x} d x

Simplify

1. 8^{0.045 x} : 1.02680 \dots^{x}

= \int 1.02680 \dots^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{1.02680 \dots ^{x}}{ln ( 1.02680 \dots )}

Simplify

\frac{1.02680 \dots ^{x}}{ln ( 1.02680 \dots )} : 37.80661 \dots \cdot 1.02680 \dots^{x}

= 37.80661 \dots \cdot 1.02680 \dots^{x}

Add a constant to the solution

= 37.80661 \dots \cdot 1.02680 \dots^{x} + C

\int \frac{( x ^{2} )}{( x + 3 ) ^{3}} d x

x \to 0 - lim ([x ln ∣ x ∣ - x])

\frac{\partial}{\partial y} (x^{ey})

y = tan^{2} (7 x)

\frac{d}{d x} (x 800 - x)

What is the integral of 1.8^{0.045x} ?
The integral of 1.8^{0.045x} is 37.80661…*1.02680…^x+C