What is the solution for (dy)/(dt)+(3t)/(t^2+1)y=(6t)/(t^2+1) ?

The solution for (dy)/(dt)+(3t)/(t^2+1)y=(6t)/(t^2+1) is y=(c_{1})/((t^2+1)^{3/2)}+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)+(3t)/(t^2+1)y=(6t)/(t^2+1)

\frac{d y}{d t} + \frac{3 t}{t ^{2} + 1} y = \frac{6 t}{t ^{2} + 1}

y = \frac{c _{1}}{( t ^{2} + 1 ) ^{\frac{3}{2}}} + 2

Solution steps

\frac{d y}{d t} + \frac{3 t}{t ^{2} + 1} y = \frac{6 t}{t ^{2} + 1}

Solve separable ODE:

y = \frac{c _{1}}{( t ^{2} + 1 ) ^{\frac{3}{2}}} + 2

y = \frac{c _{1}}{( t ^{2} + 1 ) ^{\frac{3}{2}}} + 2

\int - 3 x^{4} d x

\frac{d}{d x} (\frac{2 x - 1}{x + 9})

(x - 1)^{3}, x - 1, 0, 1

\int_{0}^{2} 2 π y (4 - y^{2}) d y

\frac{d}{d x} (\frac{x + 1}{x - 2})

What is the solution for (dy)/(dt)+(3t)/(t^2+1)y=(6t)/(t^2+1) ?
The solution for (dy)/(dt)+(3t)/(t^2+1)y=(6t)/(t^2+1) is y=(c_{1})/((t^2+1)^{3/2)}+2