What is the tangent of y=x^2-2x-2,(3,1) ?

The tangent of y=x^2-2x-2,(3,1) is y=4x-11

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tangent of y=x^2-2x-2,(3,1)

tangent of

y = x^{2} - 2 x - 2, (3, 1)

y = 4 x - 11

Solution steps

Find the slope of

y = x^{2} - 2 x - 2 : \frac{d y}{d x} = 2 x - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(3, 1) : y = 4 x - 11

y = 4 x - 11

\int \frac{1}{2} (3 sin (x) + 7) d x

y = 2 x (5 - 3 x)^{4}

x \to 0 lim (\frac{sec ( x )}{x})

x^{2} + 2, 2 x + 5

x^{2} y^{^{''}} + 2 x y^{^{'}} - 12 y = 0

What is the tangent of y=x^2-2x-2,(3,1) ?
The tangent of y=x^2-2x-2,(3,1) is y=4x-11