What is the solution for (dy)/(dx)+7(tan(7x))y=9cos(7x) ?

The solution for (dy)/(dx)+7(tan(7x))y=9cos(7x) is y=(9x)/(sec(7x))+(c_{1})/(sec(7x))

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(dy)/(dx)+7(tan(7x))y=9cos(7x)

\frac{d y}{d x} + 7 (tan (7 x)) y = 9 cos (7 x)

y = \frac{9 x}{sec ( 7 x )} + \frac{c _{1}}{sec ( 7 x )}

Solution steps

\frac{d y}{d x} + 7 (tan (7 x)) y = 9 cos (7 x)

Solve linear ODE:

y = \frac{9 x}{sec ( 7 x )} + \frac{c _{1}}{sec ( 7 x )}

y = \frac{9 x}{sec ( 7 x )} + \frac{c _{1}}{sec ( 7 x )}

\frac{d}{d x} (arccos (7 x^{2}))

\int \frac{x ^{2} + 8 x - 4}{x ^{3} - 4 x} d x

\frac{\partial}{\partial y} (2 x - \frac{y}{x})

\frac{d}{d x} (\frac{x ^{2} - 4}{x + 0.5})

y \to 0 lim (a x^{2} + b x^{3})

What is the solution for (dy)/(dx)+7(tan(7x))y=9cos(7x) ?
The solution for (dy)/(dx)+7(tan(7x))y=9cos(7x) is y=(9x)/(sec(7x))+(c_{1})/(sec(7x))