What is the tangent of y=(x-4)/(x-5),(6,2) ?

The tangent of y=(x-4)/(x-5),(6,2) is y=-x+8

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tangent of y=(x-4)/(x-5),(6,2)

tangent of

y = \frac{x - 4}{x - 5}, (6, 2)

y = - x + 8

Solution steps

Find the slope of

y = \frac{x - 4}{x - 5} : \frac{d y}{d x} = - \frac{1}{( x - 5 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(6, 2) : y = - x + 8

y = - x + 8

\frac{d}{d x} (e^{x - 5})

\int \frac{5 e ^{2 x}}{e ^{2 x} + 11 e ^{x} + 24} d x

\frac{d y}{d x} + 6 y = 7

\frac{\partial}{\partial x} (x y cos (z))

\int - x e^{\frac{y}{x}}

What is the tangent of y=(x-4)/(x-5),(6,2) ?
The tangent of y=(x-4)/(x-5),(6,2) is y=-x+8