What is the derivative of x^2+5x+4 ?

The derivative of x^2+5x+4 is 2x+5

What is the first derivative of x^2+5x+4 ?

The first derivative of x^2+5x+4 is 2x+5

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\frac{d}{d x} (x^{2} + 5 x + 4)

2 x + 5

Solution steps

\frac{d}{d x} (x^{2} + 5 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (5 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (4) = 0

= 2 x + 5 + 0

Simplify

= 2 x + 5

y = x^{2} - 4 x, (3, - 3)

\frac{d}{d x} (9.75 + 1.5 x^{3})

\int_{0}^{8} \frac{2 x - 1}{x + 1} d x

\int \frac{1}{2 x ^{2} - 2 x + 3} d x

\frac{d}{d t} (t e^{- t})

What is the derivative of x^2+5x+4 ?
The derivative of x^2+5x+4 is 2x+5
What is the first derivative of x^2+5x+4 ?
The first derivative of x^2+5x+4 is 2x+5