What is the derivative of 2x^2-2x+c ?

The derivative of 2x^2-2x+c is 4x-2

What is the first derivative of 2x^2-2x+c ?

The first derivative of 2x^2-2x+c is 4x-2

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\frac{d}{d x} (2 x^{2} - 2 x + c)

4 x - 2

Solution steps

\frac{d}{d x} (2 x^{2} - 2 x + c)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (2 x) + \frac{d c}{d x}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (2 x) = 2

\frac{d c}{d x} = 0

= 4 x - 2 + 0

Simplify

= 4 x - 2

\frac{d ^{2}}{d x ^{2}} (x (2 x + 1)^{5})

\int - 4 x e^{x} d x

y^{^{'}} + (tan (x)) y = cos (x)

\frac{d}{d x} (\frac{x ^{3} - 3 x ^{2} + 4}{x ^{2}})

\frac{1}{( s - 5 ) ^{4}}

What is the derivative of 2x^2-2x+c ?
The derivative of 2x^2-2x+c is 4x-2
What is the first derivative of 2x^2-2x+c ?
The first derivative of 2x^2-2x+c is 4x-2