What is the integral of (ln(t))/(t^2) ?

The integral of (ln(t))/(t^2) is -(ln(t))/t-1/t+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (ln(t))/(t^2)

\int \frac{ln ( t )}{t ^{2}} d t

- \frac{ln ( t )}{t} - \frac{1}{t} + C

Solution steps

\int \frac{ln ( t )}{t ^{2}} d t

Apply Integration By Parts

: - \frac{ln ( t )}{t} - \int - \frac{1}{t ^{2}} d t

= - \frac{ln ( t )}{t} - \int - \frac{1}{t ^{2}} d t

\int - \frac{1}{t ^{2}} d t = \frac{1}{t}

= - \frac{ln ( t )}{t} - \frac{1}{t}

Add a constant to the solution

= - \frac{ln ( t )}{t} - \frac{1}{t} + C

\int 2 e^{x} sinh (x) d x

g (y) = - \frac{y}{( y ^{2} + 1 ) ^{\frac{3}{2}}}

\int ln (x^{2} + 15 x + 44) d x

\int \frac{1}{( 484 + x ^{2} ) ^{\frac{3}{2}}} d x

\frac{3 ^{2}}{( s + 3 ) ^{2}} \cdot \frac{1}{s}

What is the integral of (ln(t))/(t^2) ?
The integral of (ln(t))/(t^2) is -(ln(t))/t-1/t+C