What is the solution for 9y^{''}-7y=0 ?

The solution for 9y^{''}-7y=0 is y=c_{1}e^{(sqrt(7)t)/3}+c_{2}e^{-(sqrt(7)t)/3}

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9y^{''}-7y=0

9 y^{^{''}} - 7 y = 0

y = c_{1} e^{\frac{7 t}{3}} + c_{2} e^{- \frac{7 t}{3}}

Solution steps

9 y^{''} (t) - 7 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{7 t}{3}} + c_{2} e^{- \frac{7 t}{3}}

y = c_{1} e^{\frac{7 t}{3}} + c_{2} e^{- \frac{7 t}{3}}

\frac{d}{d x} (\frac{40}{x + 1})

\frac{( s + 2 )}{s ^{2} + 4}

\int 1 tan^{2} (x) d x

g (x) = 14 (1. 7^{x})

\frac{\partial}{\partial y} (e^{3 x})

What is the solution for 9y^{''}-7y=0 ?
The solution for 9y^{''}-7y=0 is y=c_{1}e^{(sqrt(7)t)/3}+c_{2}e^{-(sqrt(7)t)/3}