What is the derivative of x^2+4x+4 ?

The derivative of x^2+4x+4 is 2x+4

What is the first derivative of x^2+4x+4 ?

The first derivative of x^2+4x+4 is 2x+4

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\frac{d}{d x} (x^{2} + 4 x + 4)

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (4) = 0

= 2 x + 4 + 0

Simplify

= 2 x + 4

\int x 3^{x} d x

\frac{d}{d x} (\frac{csc ( x )}{cot ( x )})

\int \frac{2 x ^{4} - 8 x ^{3} - 6 x ^{2} + 4}{x ^{3}} d x

y^{^{''}} - 4 y^{^{'}} + 4 y = t^{- 5} e^{2 t}

x \to - 8 lim (x + 5)

What is the derivative of x^2+4x+4 ?
The derivative of x^2+4x+4 is 2x+4
What is the first derivative of x^2+4x+4 ?
The first derivative of x^2+4x+4 is 2x+4